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6.3 The location of a parabola with respect to the x-axis
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Schedule:
6.3 Learning goals
Theory
Practice together OR practice by yourself
Work on the homework
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Wiskunde
Middelbare school
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Good morning!
Schedule:
6.3 Learning goals
Theory
Practice together OR practice by yourself
Work on the homework
Slide 1 - Diapositive
Learning goals
At the end of the lesson I can:
Calculate the number of x-intercepts of a quadratic equation
Sketch the graph of a quadratic equation
Explain what a parameter is
Calculate with parameters
Slide 2 - Diapositive
Theory A: Parabola and discriminant
What do we calculate in the equation:
2x
2
-3x-1 = 0
We solve for x, but why did we solve for x?
Slide 3 - Diapositive
Theory A: Parabola and discriminant
What do we calculate in the equation:
2x
2
-3x-1 = 0
We solve for x, but why did we solve for x?
To find the x-intercept!
If y=0 we find the x-intercept of the graph!
Slide 4 - Diapositive
This is the graph of the formula
f(x) = 2x
2
-3x-1
How many
x-intercepts
does this graph have?
What is the
discriminant
of the equation 2x
2
-3x-1 = 0?
Slide 5 - Diapositive
This is the graph of the formula
f(x) = 2x
2
-3x-1
How many
x-intercepts
does this graph have?
The graph has 2 x-intercepts.
What is the
discriminant
of the equation 2x
2
-3x-1 = 0?
D = b
2
-4ac = (-3)
2
-4·2·-1 = 9 +8 = 17
D > 0
Slide 6 - Diapositive
This is the graph of the formula
f(x) = x
2
- 6x + 9
How many
x-intercepts
does this formula have?
What is the
discriminant
of the equation x
2
- 6x + 9 = 0?
Slide 7 - Diapositive
This is the graph of the formula
f(x) = x
2
- 6x + 9
How many
x-intercepts
does this formula have?
The graph has exactly 1 x-intercept.
The graph is
tangential
to the x-axis.
What is the
discriminant
of the equation x
2
- 6x + 9 = 0?
D = b-4ac = (-6)
2
-4·1·9 = 36 - 36= 0
D = 0
Slide 8 - Diapositive
This is the graph of the formula
f(x) = x
2
+ 4x + 7
How many
x-intercepts
does this formula have?
What is the
discriminant
of the equation x
2
+ 4x + 7 = 0?
Slide 9 - Diapositive
This is the graph of the formula
f(x) = x
2
+ 4x + 7
How many
x-intercepts
does this formula have?
The graph has 0 x-intercepts
What is the
discriminant
of the equation x
2
+ 4x + 7 = 0?
D = b
2
-4ac = 4
2
-4·1·7 = 16 - 28 = -12
D < 0
Slide 10 - Diapositive
To summarize ...
Slide 11 - Diapositive
Theory B: Functions with a parameter
Take the function f(x) = 2x
2
- 6x + p
We can fill in any number we like for P:
f(x) = 2x
2
- 6x +
3
f(x) = 2x
2
- 6x
- 15
f(x) = 2x
2
- 6x +
0
We have an infinite amount of functions!!
Slide 12 - Diapositive
Example
Given the function f(x) = 2x
2
- 6x + p and point A(-3, 30) on the graph of f.
Calculate p
Slide 13 - Diapositive
Calculate p given the function
and point A(-3,30) on the graph
f
(
x
)
=
2
x
2
−
6
x
+
p
Slide 14 - Question ouverte
Example
Given the function f(x) = 2x
2
- 6x + p and point A(-3, 30) on the graph of f.
Calculate p
A(-3, 30) gives x=
-3
and y=
30.
30
= 2(
-3
)
2
-6·(
-3
)+p
30
= 2·9 + 18 + p
30
= 36 + p
-6 = p
f(x) = 2x
2
- 6x - 6 with A(-3, 30) on the graph of f
Slide 15 - Diapositive
Take out your diaries
Homework for Thursday 1-4-2021:
Havo p. 18-20: #25-32
Slide 16 - Diapositive
Raise your hand if you want to practice (with homework questions) together on the board.
For the people at home as well, raise your hand if you want to practice together.
If you want to practice by yourself you can start on the homework.
Raise your hand
if you want to practice (with homework questions) together on the board.
For the people at home as well, raise your hand if you want to practice together.
If you want to practice by yourself you can start on the homework.
Slide 17 - Diapositive
Learning goals
At the end of the lesson I can:
Calculate the number of x-intercepts of a quadratic equation
Sketch the graph of a quadratic equation
Explain what a parameter is
Calculate with parameters
Slide 18 - Diapositive
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