6.3 The location of a parabola with respect to the x-axis

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Schedule: 
  • 6.3 Learning goals 
  • Theory
  • Practice together OR practice by yourself 
  • Work on the homework 
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WiskundeMiddelbare school

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Good morning!
Schedule: 
  • 6.3 Learning goals 
  • Theory
  • Practice together OR practice by yourself 
  • Work on the homework 

Slide 1 - Diapositive

Learning goals 
At the end of the lesson I can: 
  • Calculate the number of x-intercepts of a quadratic equation 
  • Sketch the graph of a quadratic equation 
  • Explain what a parameter is 
  • Calculate with parameters

Slide 2 - Diapositive

Theory A: Parabola and discriminant 
What do we calculate in the equation: 
2x2-3x-1 = 0 
We solve for x, but why did we solve for x? 

Slide 3 - Diapositive

Theory A: Parabola and discriminant 
What do we calculate in the equation: 
2x2-3x-1 = 0 
We solve for x, but why did we solve for x? 

To find the x-intercept! 
If y=0 we find the x-intercept of the graph!

Slide 4 - Diapositive

This is the graph of the formula f(x) = 2x2-3x-1

How many x-intercepts does this graph have? 

What is the discriminant of the equation 2x2-3x-1 = 0?

Slide 5 - Diapositive

This is the graph of the formula f(x) = 2x2-3x-1

How many x-intercepts does this graph have? 
The graph has 2 x-intercepts.

What is the discriminant of the equation 2x2-3x-1 = 0?
D = b2-4ac = (-3)2-4·2·-1 = 9 +8 = 17
D > 0 

Slide 6 - Diapositive

This is the graph of the formula f(x) = x2 - 6x + 9

How many x-intercepts does this formula have? 

What is the discriminant of the equation x2 - 6x + 9 = 0?

Slide 7 - Diapositive

This is the graph of the formula f(x) = x2 - 6x + 9

How many x-intercepts does this formula have? 
The graph has exactly 1 x-intercept. 
The graph is tangential to the x-axis.

What is the discriminant of the equation x2 - 6x + 9 = 0?
D = b-4ac = (-6)2-4·1·9 = 36 - 36= 0
D = 0 


Slide 8 - Diapositive

This is the graph of the formula f(x) = x+ 4x + 7

How many x-intercepts does this formula have? 

What is the discriminant of the equation x2 + 4x + 7 = 0?

Slide 9 - Diapositive

This is the graph of the formula f(x) = x+ 4x + 7

How many x-intercepts does this formula have? 
The graph has 0 x-intercepts 

What is the discriminant of the equation x2 + 4x + 7 = 0?
D = b2-4ac = 42-4·1·7 = 16 - 28 = -12
D < 0 

Slide 10 - Diapositive

To summarize ...

Slide 11 - Diapositive

Theory B: Functions with a parameter
Take the function f(x) = 2x- 6x + p 
We can fill in any number we like for P: 
f(x) = 2x2 - 6x + 3
f(x) = 2x2 - 6x - 15 
f(x) = 2x- 6x + 0
We have an infinite amount of functions!!

Slide 12 - Diapositive

Example
Given the function f(x) = 2x2 - 6x + p and point A(-3, 30) on the graph of f. 
Calculate p

Slide 13 - Diapositive

Calculate p given the function

and point A(-3,30) on the graph
f(x)=2x26x+p

Slide 14 - Question ouverte

Example
Given the function f(x) = 2x2 - 6x + p and point A(-3, 30) on the graph of f. 
Calculate p

A(-3, 30) gives x=-3 and y= 30. 
30 = 2(-3)2-6·(-3)+p
30 = 2·9 + 18 + p 
30 = 36 + p 
-6 = p                                                 
 f(x) = 2x2 - 6x - 6 with A(-3, 30) on the graph of f

Slide 15 - Diapositive

Take out your diaries 


Homework for Thursday 1-4-2021:
Havo                  p. 18-20: #25-32

Slide 16 - Diapositive

Raise your hand if you want to practice (with homework questions) together on the board. 

For the people at home as well, raise your hand if you want to practice together. 

If you want to practice by yourself you can start on the homework. 
Raise your hand if you want to practice (with homework questions) together on the board.

For the people at home as well, raise your hand if you want to practice together.

If you want to practice by yourself you can start on the homework. 

Slide 17 - Diapositive

Learning goals 
At the end of the lesson I can: 
  • Calculate the number of x-intercepts of a quadratic equation 
  • Sketch the graph of a quadratic equation 
  • Explain what a parameter is 
  • Calculate with parameters

Slide 18 - Diapositive