Quiz circuits, conversion and power

Quiz Circuits, Conversion Power.
1 / 19
suivant
Slide 1: Diapositive
physicsMiddelbare schoolvwoLeerjaar 2

Cette leçon contient 19 diapositives, avec quiz interactifs et diapositives de texte.

time-iconLa durée de la leçon est: 45 min

Éléments de cette leçon

Quiz Circuits, Conversion Power.

Slide 1 - Diapositive

Series & Parallel circuits

Slide 2 - Diapositive

What is the voltage
accross each bulb in this
circuit?
In a series circuit, the electrical energy from the source, the voltage, has to be divided equally when the bulbs are equal. Thus 12/3 = 4 V
A
12V
B
6V
C
4V
D
0V

Slide 3 - Quiz

What is the current at
position B?
1.5 A
B
In a series circuit, the current has no other way to go, rather than go through the entire circuit. Therefore, the current is the same in the entire circuit. 
A
0.5A
B
1.5A
C
4.5A
D
0A

Slide 4 - Quiz

What is the voltage accross
the middle bulb?
This is a parallel circuit. Every bulb is connected on one side to the positive side of the battery and on the other side to the negative side of the battery. The entire electrical energy is used across the bulb, thus the voltage across every bulb is 12V.
A
12V
B
6V
C
4V
D
0V

Slide 5 - Quiz

What is the current through
the bulb on the bottom?
6A
When all the lamps in a parallel circuit are the same, every branch in the parallel circuit carries the same amount of current through it. In this example, the 6A is divided in 3 branches with each 2 Amps of current through it. 
A
6A
B
3A
C
1A
D
2A

Slide 6 - Quiz

Conversion

Slide 7 - Diapositive

Convert:
5 A = ..... mA
5 x 1000 = 5000 mA

Slide 8 - Question ouverte

Convert:
480 mA = ..... A
480 / 1000 = 0.48 A

Slide 9 - Question ouverte

Convert:
8.6 kV = ..... V
8.6 x 1000 = 8600 V

Slide 10 - Question ouverte

Convert:
200 mV = ..... kV
(200 / 1000) / 1000 = 0.0002

Slide 11 - Question ouverte

Convert:
0.1289 kA = ...... mA
0.1289 x 1000 x 1000 = 128900 mA

Slide 12 - Question ouverte

Power
P = U x I

Slide 13 - Diapositive

Calculate the power of
Bulb 1.
12V
300mA
Bulb 1
I = 300 mA = 0.3 A
U = 12/2 = 6V (divided by 2 because of series circuit)

P = 6 x 0.3 = 1.8 W
A
12W
B
1,8W
C
1800W
D
3600W

Slide 14 - Quiz

Calculate the power of
Bulb 1.
12V
300mA
Bulb 1
In the circuit, the bulbs are connected parallelly. As the bulbs are the same, the current is divided over both bulbs. Therefore, the current through bulb 1 is also 300 mA. 
I = 300 mA = 0.3 A
U = 12 V
P = 12 x 0.3 = 3.6 W
A
12W
B
300W
C
3,6W
D
3600W

Slide 15 - Quiz

Mixed circuits

Slide 16 - Diapositive

260mA
240mA

Slide 17 - Diapositive

What are the voltages across bulb 1 till 5. Answer is as following: Bulb 1,Bulb2,Bulb3,etc.
A
12V, 6V, 12V, 6V, 12V
B
6V, 6V, 4V, 4V, 4V
C
12V, 12V, 12V, 12V, 12V
D
6V, 6V, 12V, 12V, 12V

Slide 18 - Quiz

What are the currents trough wire 6 till 9. Answer is as following: point 6, point 7, point 8, point 9
A
20 mA, 80 mA, 240 mA, 260 mA
B
240 mA, 240 mA, 240 mA, 260 mA
C
10 mA, 80 mA, 80 mA, 100 mA.
D
20 mA, 80 mA, 260 mA, 260 mA

Slide 19 - Quiz