Cette leçon contient 19 diapositives, avec quiz interactifs et diapositives de texte.
La durée de la leçon est: 45 min
Éléments de cette leçon
Quiz Circuits, Conversion Power.
Slide 1 - Diapositive
Series & Parallel circuits
Slide 2 - Diapositive
What is the voltage accross each bulb in this circuit?
In a series circuit, the electrical energy from the source, the voltage, has to be divided equally when the bulbs are equal. Thus 12/3 = 4 V
A
12V
B
6V
C
4V
D
0V
Slide 3 - Quiz
What is the current at position B?
1.5 A
B
In a series circuit, the current has no other way to go, rather than go through the entire circuit. Therefore, the current is the same in the entire circuit.
A
0.5A
B
1.5A
C
4.5A
D
0A
Slide 4 - Quiz
What is the voltage accross the middle bulb?
This is a parallel circuit. Every bulb is connected on one side to the positive side of the battery and on the other side to the negative side of the battery. The entire electrical energy is used across the bulb, thus the voltage across every bulb is 12V.
A
12V
B
6V
C
4V
D
0V
Slide 5 - Quiz
What is the current through the bulb on the bottom?
6A
When all the lamps in a parallel circuit are the same, every branch in the parallel circuit carries the same amount of current through it. In this example, the 6A is divided in 3 branches with each 2 Amps of current through it.
A
6A
B
3A
C
1A
D
2A
Slide 6 - Quiz
Conversion
Slide 7 - Diapositive
Convert: 5 A = ..... mA
5 x 1000 = 5000 mA
Slide 8 - Question ouverte
Convert: 480 mA = ..... A
480 / 1000 = 0.48 A
Slide 9 - Question ouverte
Convert: 8.6 kV = ..... V
8.6 x 1000 = 8600 V
Slide 10 - Question ouverte
Convert: 200 mV = ..... kV
(200 / 1000) / 1000 = 0.0002
Slide 11 - Question ouverte
Convert: 0.1289 kA = ...... mA
0.1289 x 1000 x 1000 = 128900 mA
Slide 12 - Question ouverte
Power
P = U x I
Slide 13 - Diapositive
Calculate the power of Bulb 1.
12V
300mA
Bulb 1
I = 300 mA = 0.3 A
U = 12/2 = 6V (divided by 2 because of series circuit)
P = 6 x 0.3 = 1.8 W
A
12W
B
1,8W
C
1800W
D
3600W
Slide 14 - Quiz
Calculate the power of Bulb 1.
12V
300mA
Bulb 1
In the circuit, the bulbs are connected parallelly. As the bulbs are the same, the current is divided over both bulbs. Therefore, the current through bulb 1 is also 300 mA.
I = 300 mA = 0.3 A
U = 12 V
P = 12 x 0.3 = 3.6 W
A
12W
B
300W
C
3,6W
D
3600W
Slide 15 - Quiz
Mixed circuits
Slide 16 - Diapositive
260mA
240mA
Slide 17 - Diapositive
What are the voltages across bulb 1 till 5. Answer is as following: Bulb 1,Bulb2,Bulb3,etc.
A
12V, 6V, 12V, 6V, 12V
B
6V, 6V, 4V, 4V, 4V
C
12V, 12V, 12V, 12V, 12V
D
6V, 6V, 12V, 12V, 12V
Slide 18 - Quiz
What are the currents trough wire 6 till 9. Answer is as following: point 6, point 7, point 8, point 9