Cette leçon contient 17 diapositives, avec quiz interactif et diapositives de texte.
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5.3b Parallel Circuits
Connecting Resistors
Slide 1 - Diapositive
https:
Slide 2 - Lien
Last week
Current is the same everywhere in series circuit.
The voltage distributes itself among the various components
Equivalent resistances (Req) can be calculated by adding the resistances together.
Req = R1 + R2 +..
Slide 3 - Diapositive
The LED lamp in the figure burns optimally at a voltage of 2.0 V. A current of 20 mA flows through the lamp. The battery supplies a voltage of 9.0 V. Calculate the value of the resistor that is needed to light the bulb at the correct voltage.
Slide 4 - Question ouverte
Elaboration:
Reminder:
Req = R1 + R2 + R3 + .....
Isource = I1 = I2 = I3 =.....
Usource = U1 + U2 + U3....
Given:
Ulamp = 2,0 V
Usource= 9,0 V
I = 20 mA = 0,020 A
Asked:
Rresistor = ?
Conclusion:
Usource= Ulamp + Uresistor
9,0 = 2,0 + Uresistor
Uresistor = 7,0 V
Rresitor = Ω
IU=0,0207,0=3,5⋅102
Slide 5 - Diapositive
This lesson
you know what a parallelcircuit is.
You can calculate the equivalent resistance of the resistors in a parallel circuit.
You can calculate the current through each resistor in a parallelcircuit
Slide 6 - Diapositive
Serie circuit
Parallel circuit
Mixed circuit
Slide 7 - Diapositive
Parallel
Circuit
Slide 8 - Diapositive
Current
The current distributes itself among the different branches.
Itot = I1 + I2 + I3 + ..
parallel
Slide 9 - Diapositive
Voltage
There is the same (source) voltage across each resistor.
(Because each component is connected directly to the source).
Usource = U1 = U2 = U3
parallel
Slide 10 - Diapositive
more resistors parallel
Resistance becomes smaller
1/ Req = 1/R1 + 1/R2 + ...
Equivalent resistance
parallel
Slide 11 - Diapositive
Exercise
Calculate:
- the equivalent resistance
- the total current
1/ Req = 1/R1 + 1/R2 + ...
R = U / I
Slide 12 - Diapositive
Given
R1 = 10 ohm, R2 = 40 ohm, U = 4V
Asked
Req en Isource
Formulas
1/ Req = 1/R1 + 1/R2
R = U/I
Elaboration
1/Req = 1/10 + 1/40 = 0,125
Req = 1/0,125 = 8 Ω
R = 8 ohm, U = 4V
Isource = U/R = 4/8 = 0,5 A
=
Slide 13 - Diapositive
Circuitry Analysis - Parallel
Step 1: Simplify all parallel 'blocks'.
Step 2: Calculate Req.
Step 3: Calculate Isource.
Step 4: Calculate the voltage across each 'block'.
Step 5: Calculate the individual current through each resistor
Slide 14 - Diapositive
Practice
Step 2:
Req
Step 3:
Isource
Step 4:
U1...
Step 5:
I1....
Slide 15 - Diapositive
Reasoning
2 lights are in parallel. Then switch S is opened.
What happens with the current through the lamp on the right? (0)
And through the lamp on the left? (stays same)
Slide 16 - Diapositive
Individual assignment
Homework: 2 + 5 t/m 9
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