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5.5 and 5.6 Pitch and Frequency,, calculations sound
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Science
Middelbare school
vwo
Leerjaar 1
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Slide 1 - Diapositive
Slide 2 - Diapositive
Recap
Four wave properties:
1. Wave length
2. Amplitude
3. Frequency
4. Speed
Slide 3 - Diapositive
Slide 4 - Diapositive
Slide 5 - Diapositive
v
=
f
⋅
λ
Slide 6 - Diapositive
Slide 7 - Diapositive
Slide 8 - Vidéo
You saw the frequency increasing. What happened to the pitch if the frequency increases? As the f increases pitch increases too.
A. What was the highest frequency you heard?
Somwhere between 20 to 23000 Hz.
Slide 9 - Diapositive
Slide 10 - Diapositive
For this exercise use the table at the previous page. You only need two names.
Animal which can hear the highest frequency
Animal that hears the lowest frequency
Neither of the two choices
Elephant
Porpoise
Bats
Dog
Cat
Chicken
Killer Whale
Slide 11 - Question de remorquage
What frequency can be heard by all animals?
A
16 Hz
B
2.000 Hz
C
150.000 Hz
D
None of the one mentioned
Slide 12 - Quiz
Slide 13 - Diapositive
Two formulas to calculate the speed of sound
s
p
e
e
d
=
t
i
m
e
d
i
s
t
a
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c
e
s
p
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d
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f
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d
=
w
a
v
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l
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g
t
h
⋅
f
r
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Slide 14 - Diapositive
s
p
e
e
d
=
t
i
m
e
d
i
s
t
a
n
c
e
v
=
t
d
v
: speed in m/s
d
: distance in m
t
: time in s
3
=
2
6
Slide 15 - Diapositive
v
s
: the speed of sound (m/s)
λ
: wavelength (m)
f
: frequency (Hz)
s
p
e
e
d
o
f
s
o
u
n
d
=
w
a
v
e
l
e
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h
⋅
f
r
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q
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c
y
v
s
= λ • f
6
=
2
⋅
3
Slide 16 - Diapositive
Slide 17 - Diapositive
Formula frequency
f = 1/T where,
f: frequency in hertz (Hz)
T: time needed for one vibration in seconds
T=1/f
Slide 18 - Diapositive
Slide 19 - Diapositive
Definition supersonic and Mach
Supersonic: faster than speed of sound
Mach 1 = speed of sound in air = 330 m/s
Mach 3 = 330× 3= 990 m/s
Slide 20 - Diapositive
Opgave
a sound wave were observed to travel a distance of 700 meters in 2 seconds. Calculate its speed.
Given: d= 700 meter , t= 2 s
Asked: v=?
v=d/t. v= 700/ 2= 350 m/s
Slide 21 - Diapositive
Opgave
What is the speed of a sound wave with a frequency of 2 kHz and a wavelength of 35 cm?
Given: f= 2kHz. = 2000 Hz.
λ= 35 cm = 0.35 m
Asked: v=?
v = λ • f = 0.35× 2000= 700 m/s
Slide 22 - Diapositive
Calculating the speed of sound using echoes
A girl stands 102 m away from a wall and claps two wooden blocks together. She hears an echo after 0.6 s.Calculate the speed of sound in air.
Given: t = 0.6 s. d=102 + 102 = 204 m.
Asked: v=?
v=d/t = 204÷ 0.6=340 m/s
Or v=d/t. v= 102÷ 0.30 = 340 m/s
Slide 23 - Diapositive
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