Inverse relationships 2

Recap 12.1, 12.2, 12.3

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Slide 1: Diapositive

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Cette leçon contient 44 diapositives, avec quiz interactifs et diapositives de texte.

Éléments de cette leçon

Recap 12.1, 12.2, 12.3

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Slide 1 - Diapositive

Today

Start lesson (5 min)
Recap (20 min)
Bettermarks (20 min)
Questions together (15 min)
Bettermarks (15 min)
End lesson (5 min)

Slide 2 - Diapositive

Graphing

Slide 3 - Diapositive

Slide 4 - Diapositive

L i n e a i r g r a p h

Slide 5 - Diapositive

y = m x + b

L i n e a i r g r a p h

Slide 6 - Diapositive

y = - 2 x + 4

y = m x + b

L i n e a i r g r a p h

Slide 7 - Diapositive

y = - 2 x + 4

y = m x + b

m = \frac{​ r i s e ​ ​}{​ r u n ​}

L i n e a i r g r a p h

Slide 8 - Diapositive

y = - 2 x + 4

y = m x + b

m = \frac{​ r i s e ​ ​}{​ r u n ​}

L i n e a i r g r a p h

Slide 9 - Diapositive

y = - 2 x + 4

y = m x + b

m = \frac{​ r i s e ​ ​}{​ r u n ​}

L i n e a i r g r a p h

P a r a b o l a

Slide 10 - Diapositive

y = - 2 x + 4

y = m x + b

y = a x^{​ 2 ​ ​} + b x + c

m = \frac{​ r i s e ​ ​}{​ r u n ​}

L i n e a i r g r a p h

P a r a b o l a

Slide 11 - Diapositive

y = - 2 x + 4

y = x^{​ 2 ​ ​} + 2 x - 4

y = m x + b

y = a x^{​ 2 ​ ​} + b x + c

m = \frac{​ r i s e ​ ​}{​ r u n ​}

L i n e a i r g r a p h

P a r a b o l a

Slide 12 - Diapositive

y = - 2 x + 4

y = x^{​ 2 ​ ​} + 2 x - 4

y = m x + b

y = a x^{​ 2 ​ ​} + b x + c

m = \frac{​ r i s e ​ ​}{​ r u n ​}

L i n e a i r g r a p h

P a r a b o l a

Slide 13 - Diapositive

y = - 2 x + 4

y = x^{​ 2 ​ ​} + 2 x - 4

y = m x + b

y = a x^{​ 2 ​ ​} + b x + c

m = \frac{​ r i s e ​ ​}{​ r u n ​}

L i n e a i r g r a p h

P a r a b o l a

H y p e r b o l a

Slide 14 - Diapositive

y = - 2 x + 4

y = x^{​ 2 ​ ​} + 2 x - 4

y = \frac{​ 1 ​ ​}{​ x + 3 ​} + 2

y = m x + b

y = a x^{​ 2 ​ ​} + b x + c

m = \frac{​ r i s e ​ ​}{​ r u n ​}

L i n e a i r g r a p h

P a r a b o l a

H y p e r b o l a

Slide 15 - Diapositive

Find the slope of the graph.

timer

1:00

Slide 16 - Diapositive

Give the slope of the graph.

Slide 17 - Question ouverte

Find the slope of the graph.

Slide 18 - Diapositive

Find the formula for the graph.

timer

1:00

Slide 19 - Diapositive

Give the formula of the graph.

Slide 20 - Question ouverte

Find the formula for the graph.

Slide 21 - Diapositive

Question

Find the missing place in the table

-2

-1

y = x^{​ 2 ​ ​} - 2 x + 5

timer

1:30

Slide 22 - Diapositive

Find the missing place in the table.

Slide 23 - Question ouverte

Question

Find the missing place in the table

-2

-1

y = x^{​ 2 ​ ​} - 2 x + 5

Slide 24 - Diapositive

Question

Find the missing place in the table

-2

-1

y = x^{​ 2 ​ ​} - 2 x + 5

Slide 25 - Diapositive

Give the two formulas for the asymptotes.

x = ...

y = ...

timer

1:00

Slide 26 - Diapositive

Give the two formulas for the asymptotes. (x = ... and y = ...)

Slide 27 - Question ouverte

Give the two formulas for the asymptotes.

x = ...

y = ...

Slide 28 - Diapositive

Give the two formulas for the asymptotes.

x = ...

y = ...

y = \frac{​ 1 ​ ​}{​ x - 3 ​} - 2

Slide 29 - Diapositive

Bettermarks

Bettermarks 12.2 and 12.3
20 min
Raise your finger if you have any questions or when you're finished
Communicate in English please

timer

20:00

Slide 30 - Diapositive

Question together

Put your Ipad down and grab your notebook

Slide 31 - Diapositive

Question 10 Bettermarks

Slide 32 - Diapositive

What is the area of a garden if 5 people rent one?

Slide 33 - Diapositive

The area of one garden is 9 m². How many people have rented a garden?

Slide 34 - Diapositive

Solving inverse equations

Find t if N = 23 in the formula

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

Slide 35 - Diapositive

Solving inverse equations

Find t if N = 23 in the formula

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

Slide 36 - Diapositive

Solving inverse equations

Find t if N = 23 in the formula

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

23 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

Slide 37 - Diapositive

Solving inverse equations

Find t if N = 23 in the formula

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

23 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

28 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​}

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

Slide 38 - Diapositive

Solving inverse equations

Find t if N = 23 in the formula

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

23 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

28 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​}

3 + t = \frac{​ 1 4 0 ​ ​}{​ 2 8 ​}

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

Slide 39 - Diapositive

Solving inverse equations

Find t if N = 23 in the formula

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

23 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

28 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​}

3 + t = \frac{​ 1 4 0 ​ ​}{​ 2 8 ​}

3 + t = 5

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

Slide 40 - Diapositive

Solving inverse equations

Find t if N = 23 in the formula

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

23 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

28 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​}

3 + t = \frac{​ 1 4 0 ​ ​}{​ 2 8 ​}

3 + t = 5

t = 2

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

Slide 41 - Diapositive

Solving inverse equations

Find t if N = 23 in the formula

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

23 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

28 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​}

3 + t = \frac{​ 1 4 0 ​ ​}{​ 2 8 ​}

3 + t = 5

t = 2

2 = \frac{​ 6 ​ ​}{​ 3 ​}

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

Slide 42 - Diapositive

Solving inverse equations

Find t if N = 23 in the formula

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

23 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

28 = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​}

3 + t = \frac{​ 1 4 0 ​ ​}{​ 2 8 ​}

3 + t = 5

t = 2

2 = \frac{​ 6 ​ ​}{​ 3 ​}

3 = \frac{​ 6 ​ ​}{​ 2 ​}

N = \frac{​ 1 4 0 ​ ​}{​ 3 + t ​} - 5

Slide 43 - Diapositive

Bettermarks

Bettermarks 12.2 and 12.3
Until 14:40
Raise your finger if you have any questions or when you're finished
Communicate in English please

Slide 44 - Diapositive

Inverse relationships 2

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