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Factoring binomials
Factoring binomials
You need your Ipad and your notebook
1 / 30
volgende
Slide 1:
Tekstslide
Wiskunde
Middelbare school
vwo
Leerjaar 3
In deze les zitten
30 slides
, met
interactieve quizzen
,
tekstslides
en
1 video
.
Start les
Bewaar
Deel
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Onderdelen in deze les
Factoring binomials
You need your Ipad and your notebook
Slide 1 - Tekstslide
Today
Start (5 min)
New subject (25 min)
Bettermarks (20 min)
Exercise together (10 min)
Bettermarks (15 min)
End lesson (5 min)
Slide 2 - Tekstslide
Slide 3 - Video
Slide 4 - Tekstslide
f
(
x
)
=
−
3
x
2
+
4
x
+
3
Slide 5 - Tekstslide
f
(
x
)
=
−
3
x
2
+
4
x
+
3
x
=
2
a
−
b
±
√
b
2
−
4
a
c
Slide 6 - Tekstslide
Find a, b and c in the formula
f
(
x
)
=
−
3
x
2
+
4
x
+
3
timer
1:00
Slide 7 - Open vraag
f
(
x
)
=
−
3
x
2
+
4
x
+
3
x
=
2
a
−
b
±
√
b
2
−
4
a
c
a
=
−
3
b
=
4
c
=
3
Slide 8 - Tekstslide
Solving with the quadratic formula
f
(
x
)
=
−
3
x
2
+
4
x
+
3
Slide 9 - Tekstslide
Solving with the quadratic formula
0
=
−
3
x
2
+
4
x
+
3
Slide 10 - Tekstslide
Solving with the quadratic formula
0
=
−
3
x
2
+
4
x
+
3
x
=
2
a
−
b
±
√
b
2
−
4
a
c
Slide 11 - Tekstslide
Solving with the quadratic formula
0
=
−
3
x
2
+
4
x
+
3
x
=
2
a
−
b
±
√
b
2
−
4
a
c
a
=
−
3
b
=
4
c
=
3
Slide 12 - Tekstslide
Solving with the quadratic formula
0
=
−
3
x
2
+
4
x
+
3
x
=
2
a
−
b
±
√
b
2
−
4
a
c
a
=
−
3
b
=
4
c
=
3
x
=
2
⋅
−
3
−
4
±
√
4
2
−
4
⋅
−
3
⋅
3
Slide 13 - Tekstslide
Solving with the quadratic formula
or
0
=
−
3
x
2
+
4
x
+
3
x
=
2
a
−
b
±
√
b
2
−
4
a
c
a
=
−
3
b
=
4
c
=
3
x
=
2
⋅
−
3
−
4
±
√
4
2
−
4
⋅
−
3
⋅
3
x
=
−
6
−
4
+
√
5
2
x
=
−
6
−
4
−
√
5
2
Slide 14 - Tekstslide
Solving with the quadratic formula
or
or
0
=
−
3
x
2
+
4
x
+
3
x
=
2
a
−
b
±
√
b
2
−
4
a
c
a
=
−
3
b
=
4
c
=
3
x
=
2
⋅
−
3
−
4
±
√
4
2
−
4
⋅
−
3
⋅
3
x
=
−
6
−
4
+
√
5
2
x
=
−
6
−
4
−
√
5
2
x
≈
−
0
,
5
4
x
≈
1
,
8
7
Slide 15 - Tekstslide
Remove the brackets
m
(
m
−
3
)
timer
0:45
A
2
m
−
3
B
m
2
−
3
C
m
2
−
3
m
D
2
m
−
3
m
Slide 16 - Quizvraag
Remove the brackets
m
(
m
−
3
)
Slide 17 - Tekstslide
Quadratic formulas
c = 0
y
=
4
x
2
−
8
x
+
1
2
y
=
−
x
2
+
2
5
x
y
=
x
2
y
=
9
x
2
−
1
3
y
=
−
5
x
2
+
2
x
y
=
x
2
+
9
x
y
=
3
x
2
−
1
2
x
y
=
−
x
2
−
x
Slide 18 - Tekstslide
13.2: Factoring binomials
You can factorize (=make brackets) a formula if c = 0. You have to find the biggest number and letter, that is a divisor of both terms
Example: Factor
You can divide both and by
Answer:
y
=
6
x
2
+
4
x
6
x
2
4
x
2
x
y
=
2
x
(
3
x
+
2
)
6
x
2
:
2
x
=
3
x
4
x
:
2
x
=
2
timer
4:00
Slide 19 - Tekstslide
Example
Factor
1
6
x
2
−
1
2
x
Slide 20 - Tekstslide
Factor
1
8
p
2
+
3
p
timer
1:30
Slide 21 - Open vraag
7.2 Solving equations
Example: Solve
Step 1, factorize:
Step 2, make two equations: or
Step 3, use the balance method: or
Step 4, answer: or
1
5
m
2
+
6
m
=
0
3
m
(
5
m
+
2
)
=
0
3
m
=
0
5
m
+
2
=
0
m
=
0
5
m
=
−
2
m
=
−
5
2
m
=
0
timer
3:00
Slide 22 - Tekstslide
Example
Solve
2
p
2
+
7
p
=
0
Slide 23 - Tekstslide
Solve the equation
2
x
2
+
8
x
=
0
timer
2:30
Slide 24 - Open vraag
Solve the equation
2
x
2
+
8
x
=
0
Slide 25 - Tekstslide
Bettermarks
Work on 13.2
20 min
Raise your finger if you have any questions or when you're finished
Communicate in English please
timer
20:00
Slide 26 - Tekstslide
Question together
Ipads on the corner of the table
Slide 27 - Tekstslide
13.2 Question 16
Slide 28 - Tekstslide
Question 15
Slide 29 - Tekstslide
Bettermarks
Work on 13.2
Until the end of the lesson
Raise your finger if you have any questions or when you're finished
Communicate in English please
Slide 30 - Tekstslide
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