Chapter 6 Movement

• physics
• Middelbare school
• havo, vwo
• Leerjaar 2

Movement

Stopping distance

Stopping distance = reaction distance + braking distance

Reaction distance = v x t

v = speed in m/s and t = time in seconds

Braking distance is given or can be find in a graph.

Assignment 40

a. Braking distance at 120 km/h is 90 m (fig. 28 page 197)

b. G. v = 120 km/h = 120:3.6 = 33.3 m/s

     t = 0.8 s

     A. s

     S. v = s / t     s = v xt = 33.3 x 0.8 = 26.6 m

c. Stopping distance = reaction distance + breaking distance

stopping distance = 26.6 m + 90 m = 116.6 metres

Assignment 41

G. v = 40 km/h = 40 : 3.6 = 11.11 m/s

schild = 22 m;          treaction = 0.9 s

A. s is not 22 m

S. breaking distance at 40 km/h = 10 m (fig. 28 page 197)

s = v x t = 11.11 x 0.9 = 10 m

stopping distance = reaction distance + breaking distance

stopping distance = 10 m + 10 m = 20 m. They do not collide.

Check answers

Chapter 6

Work and repeat

Do assignment 1 till 14 (page 211 and 212)

Work with G.A.S. if required

Remember: 

v = s/t

km/h to m/s (:3.6)

Chapter 5

Work and repeat

Do assignment 1 till 11, 13 till 16

Test Yourself Chapter 5

Work with G.A.S. if required

Remember: 

P = U x I

mA to A (: 1000)

allowed

Check your answers

Good luck with your test week!