23/10: Reacting masses

• Chemistry
• Secondary Education

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CHEMISTRY 10

                   20: Reacting masses

Week 11

Good Afternoon!

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Classwork 9: Stoichiometry (part 2)

Apply your learned knowledge and skills:

Choose one. (2 marks)

Write the word and balanced symbol equations.

Option 1: When added to dilute hydrochloric acid, copper (II) carbonate fizzes and releases carbon dioxide gas. The resulting solution is copper (II) chloride and water.

Option 2: Magnesium carbonate fizzes and releases carbon dioxide gas when added to dilute sulfuric acid. The resulting solution is magnesium sulfate and water.

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CHEMISTRY 10

                   20: Reacting masses

Week 11

calculate the Aᵣ or Mᵣ of atoms and molecules/ ions.

calculate reacting masses in simple proportions.

assess my thinking and how I learn to identify growth areas and improve my learning.

What mass of carbon dioxide would be produced if 6 g of carbon was completely combusted?

What mass of carbon dioxide would be produced if 6 g of carbon was completely combusted?

C + O₂ → CO₂

Why do chemists often need to be able to show the relative masses of the atoms involved in a chemical process?

• Chemists often need to know how much of a substance has been formed or used up during a chemical reaction. This is particularly important in the chemical industry, where the substances being reacted (the reactants) and the substances being produced (the products) are worth thousands of dollars!

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Word equation

Symbol equation

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Word equation

Symbol equation

Symbol equation with state symbols

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Word equation

Symbol equation

Symbol equation with state symbols

Balanced symbol equation with state symbols

Balanced chemical (symbol) equation

• a summary of a chemical reaction using chemical formulae
• the total number of atoms involved is the same on both the reactant and product sides of the equation

Balanced chemical (symbol) equation

• a summary of a chemical reaction using chemical formulae
• the total number of atoms involved is the same on both the reactant and product sides of the equation

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Balanced chemical (symbol) equation

• a summary of a chemical reaction using chemical formulae
• the total number of atoms involved is the same on both the reactant and product sides of the equation

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Balanced chemical (symbol) equation

• a summary of a chemical reaction using chemical formulae
• the total number of atoms involved is the same on both the reactant and product sides of the equation

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

REACTANTS

PRODUCTS

K = 2 X 1 = 2

H = 2 X 2 = 4

O = 2 X 1 = 2

K = 2 X 1 = 2

H = 2 X 1 = 2   +    H = 2

O = 2 X 1 = 2

I can write word equations and symbol equations to show how reactants form products with state symbols

Yes, I can confidently do it.

Yes, I can but need more practice.

No, I lack confidence so I need more practice or ask help from my teacher.

Sample 1

• Iron rusts because it reacts with oxygen in the air to form a compound called iron (III) oxide.

a chemical reaction → a word equation → a symbol equation with state symbols → balanced symbol equation

Sample 2

• 2NaOH (solid) + H₂SO₄ (aqueous) → Na₂SO₄ (aqueous)+ 2H₂O (liquid)

a chemical reaction ⬅️ a word equation ⬅️ a symbol equation with state symbols ⬅️ balanced symbol equation

I can deduce the symbol equation with state symbols for a chemical reaction, given relevant information.

Yes, I can confidently do it.

Yes, I can but need more practice.

No, I lack confidence so I need more practice or ask help from my teacher.

Practice your skill:

Part 1. Choose one only.

(a) Sodium reacts vigorously with water to give a sodium hydroxide solution; hydrogen gas is also given off.

(b) A white precipitate is formed when silver nitrate is added to sodium chloride solution. This white precipitate is silver chloride, which is highly insoluble in water. This is why silver nitrate solution is used to detect the presence of halide ions.

a chemical reaction → a word equation → a symbol equation with state symbols → balanced symbol equation

Practice your skill:

Part 2. Choose one only.

 (a) 2K (solid) + 2HCl (liquid) → 2KCl (aqueous) + H₂ (gas)

 (b) 2Al (solid) + 3Cl₂ (gas) → 2AlCl₃ (solid) 

a chemical reaction ⬅️ a word equation ⬅️ a symbol equation with state symbols ⬅️ balanced symbol equation

Share your thought process in calculating the relative molecular/formula mass.

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STEM Project

Building a Futuristic City Scale Model

Week 11

Share your thought process in calculating the relative molecular/formula mass.