An electric kettle using a current of 2.17 A takes 1 minute and 54 seconds to boil the water.
Calculate the energy consumption of the kettle in kJ.
Answer:
F: E = P · t
I: t = 1m 54s I = 2.17 U = 230v (knowledge!)
C:
- P = U · I = 230 · 2.17 = 499.1 W
- t = 60 + 54 = 114 s
- E = 499.1 · 114 = 56 897 J --> 56.9 kJ
A: 56.9 kJ