Lesson 11

Electricity — Ohm's Law

1 / 18

Slide 1: Tekstslide

NaskMiddelbare schoolhavo, vwoLeerjaar 2

In deze les zitten 18 slides, met tekstslides en 1 video.

Lesduur is: 45 min

Onderdelen in deze les

Electricity — Ohm's Law

Slide 1 - Tekstslide

This lesson

Properly understanding voltage
Ohm's law
Practice exercise (the homework)
Worksheet Ohm's law

Slide 2 - Tekstslide

Learning goals

You can explain what current, resistance and voltage are in your own words and name the correct unit for each.

You can name Ohm's law in words and in symbols and you can do calculations with it.

You are able to rearrange Ohm's law.

Slide 3 - Tekstslide

Current, voltage and resistance.

Current: the flow of charged particles from one point in a circuit to another. Expressed in amperes (Coulomb / second)

Voltage: The difference in electrical potential energy between two points in a circuit. Expressed in volts (Joules / coulomb)

Resistance: The opposition to the flow of charged particles. Expressed in Ohms.

Slide 4 - Tekstslide

Slide 5 - Tekstslide

Circuit lab

Ohm's law

Slide 6 - Tekstslide

Current, voltage and resistance.

Current: the flow of charged particles from one point in a circuit to another. Expressed in amperes (Coulomb / second)

Voltage: The difference in electrical potential energy between two points in a circuit. Expressed in volts (Joules / second)

Resistance: The opposition to the flow of charged particles. Expressed in Ohms.

Slide 7 - Tekstslide

Slide 8 - Video

Ohm's law

C u r r e n t = \frac{​ V o l t a g e ​ ​}{​ R e s i s t a n c e ​}

I = \frac{​ V ​ ​}{​ R ​}

Physical quantity

Current (I)
Voltage (V)
Resistance (R)

Current: the flow of charged particles from one point in a circuit to another. Expressed in amperes (Coulomb / second)

Voltage: The difference in electrical potential energy between two points in a circuit. Expressed in volts (Joules / second)

Resistance: The opposition to the flow of charged particles. Expressed in Ohms.

Unit

CAmpere (A)
Volt (V)
Ohm (Ω)

Slide 9 - Tekstslide

3 lamps are connected to a battery in a parallel circuit. The battery supplies the circuit with 2.4 Ampere.

Because of its resistance, the second lamp gets 2/3 of the current supplied to the circuit. The rest of the current gets divided evenly over the other two lamps.

The voltage over the battery is 6 Volts.

Calculate the resistance of each lamp.

Slide 10 - Tekstslide

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 11 - Tekstslide

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 12 - Tekstslide

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 13 - Tekstslide

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 14 - Tekstslide

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 15 - Tekstslide

Practice exercise

A) An average refrigerator works on a voltage of 120 Volts. A normal resistance for a refrigerator can be 45 Ohm. Calculate the current flowing through a refrigerator that has these properties.

B) What would the resistance on a fridge that has the same voltage have to be if it has a current of 2.4 Ampere flowing through it?

Slide 16 - Tekstslide

Worksheet Ohm's law

Slide 17 - Tekstslide

Learning goals

You can explain what current, resistance and voltage are in your own words and name the correct unit for each.

You can name Ohm's law in words and in symbols and you can do calculations with it.

You are able to rearrange Ohm's law.

Slide 18 - Tekstslide

Lesson 11

Onderdelen in deze les

Slide 1 - Tekstslide

Slide 2 - Tekstslide

Slide 3 - Tekstslide

Slide 4 - Tekstslide

Slide 5 - Tekstslide

Slide 6 - Tekstslide

Slide 7 - Tekstslide

Slide 8 - Video

Slide 9 - Tekstslide

Slide 10 - Tekstslide

Slide 11 - Tekstslide

Slide 12 - Tekstslide

Slide 13 - Tekstslide

Slide 14 - Tekstslide

Slide 15 - Tekstslide

Slide 16 - Tekstslide

Slide 17 - Tekstslide

Slide 18 - Tekstslide

Meer lessen zoals deze

Lesson 12

Lesson 5

Lesson 1

Lesson 4 — current, voltage and resistance

Lesson 2 — Resistance

Questiosn Ohm's law – answers

Lesson 10

9.8 How components affect the current