Chapter 5: Preparing for the test

Preparing for the test
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Slide 1: Tekstslide
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In deze les zitten 47 slides, met interactieve quizzen, tekstslides en 6 videos.

time-iconLesduur is: 45 min

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Preparing for the test

Slide 1 - Tekstslide

Preparing the test
Hi,

I had some technical issues at home with my video software which I could not solve in time. So, no video but instead a lessonUp with a voice over!

I will go over the main definitions and principles of this chapter once more. I hope you will find it helpfull. 

Do not forget to practice yourselves.
 

Slide 2 - Tekstslide

Slide 3 - Tekstslide

Slide 4 - Tekstslide

Whenever an object is at rest or moving at constant speed in a straight line (constant velocity), Newton’s 1st Law of motion must come to your mind.

Concepts on Newton’s 1st Law are: Net force = resultant force = 0N, a = 0m/s2 , all forces are balanced.


If the object is accelerating or decelerating, that means the forces are unbalanced. Newton’s 2nd Law of Motion must come to your mind.

Concepts on Newton’s 2nd Law are: There is net force or resultant force, unbalanced forces, there is acceleration or deceleration.

Slide 5 - Tekstslide

Slide 6 - Tekstslide

Slide 7 - Tekstslide

Misconception

Slide 8 - Tekstslide

Slide 9 - Tekstslide

Slide 10 - Tekstslide

Slide 11 - Tekstslide

Slide 12 - Tekstslide

Slide 13 - Tekstslide

Slide 14 - Video

A
B
C
D
E
A
B
C
D
E
a = +
a = 0
a = -
a = -
a = +

Slide 15 - Tekstslide

Slide 16 - Tekstslide

Slide 17 - Tekstslide

Slide 18 - Tekstslide

Slide 19 - Tekstslide

Slide 20 - Tekstslide

Slide 21 - Tekstslide

Slide 22 - Tekstslide

Slide 23 - Tekstslide

Slide 24 - Tekstslide

Slide 25 - Tekstslide

Slide 26 - Tekstslide

Slide 27 - Tekstslide

Slide 28 - Video

Slide 29 - Video

Slide 30 - Tekstslide

Slide 31 - Tekstslide

Slide 32 - Tekstslide

Slide 33 - Tekstslide

Slide 34 - Tekstslide

Slide 35 - Video

Slide 36 - Video

Slide 37 - Tekstslide

Slide 38 - Tekstslide

Slide 39 - Tekstslide

At what time does B overtake A ?

Slide 40 - Tekstslide

Surface:
(16 x 10) + 16 x (ΔT) =
160 + 16 ΔT
Surface:
1/2 x (20 x 10) + 20 x (ΔT) =
100 + 20 ΔT
100 + 20 ΔT = 160 + 16 ΔT 
20 ΔT - 16 ΔT = 160 - 100 
4 ΔT = 60
ΔT = 15 s
t = 10 + 15 s = 25 s


Proof that it is correct:

100 + 20 ΔT = 100 + 20 x 15 = 400 m
160 + 16 ΔT = 160 + 16 x 15 = 400 m



surfaces should be equal
ΔT
ΔT

Slide 41 - Tekstslide

Slide 42 - Tekstslide

The velocity-time graph of an object moving in a straight line is shown. If the average velocity is 20 m.s-1. The acceleration [m.s-2] from A to B is


answer

Slide 43 - Tekstslide

Slide 44 - Video

What length of time corresponds to the
distance between
X and Y on the tape?
A
0,10 s
B
0,11 s
C
0,17 s
D
0,18 s

Slide 45 - Quizvraag

At what speed was the tape moving between X and Y?
A
2,5 cm/s
B
5 cm/s
C
50 cm/s
D
100 cm/s

Slide 46 - Quizvraag

In the figure the distance moved by a trolly in successive seconds is given by the spacing between the dots
A
2 cm/s
B
3 cm/s
C
4 cm/s
D
6 cm/s

Slide 47 - Quizvraag