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6.4 Braking and collisions
6.4 Braking and collisions
2THa
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Natuurkunde
Middelbare school
havo, vwo
Leerjaar 2
This lesson contains
18 slides
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interactive quizzes
and
text slides
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Lesson duration is:
30 min
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6.4 Braking and collisions
2THa
Slide 1 - Slide
6.4 Braking and collisions
Slide 2 - Slide
In traffic you always have to able to stop in time without having a collision.
Slide 3 - Slide
What factors will influence the braking distance?
A
Mass of the car
B
Braking force
C
Speed of the car
D
All answers above
Slide 4 - Quiz
The higher the initial speed,
the longer the braking distance.
Slide 5 - Slide
The greater the mass of the vehicle,
the longer the breaking distance.
Slide 6 - Slide
If the road is slippery you have to brake slowly, othewise the car will slip.
Slide 7 - Slide
And sometimes the brakes just fail....
Slide 8 - Slide
Braking distance
Depends on:
Initial speed
;
the faster you are going, the greater the braking distance
Total mass
;
the greater the mass the greater the braking distance
Braking force
;
the harder the brakes are pressed the shorter the braking distance
Slide 9 - Slide
Slide 10 - Slide
Stopping distance = reaction distance + braking distance
Slide 11 - Slide
Reaction time
Make pairs
Fold you paper 3x double
Nr.1 has his hand open
Nr.2 determince when to let go
Nr.1 has to react
Slide 12 - Slide
Reaction distance
Reaction distance = reaction time x velocity
The reaction time in normal conditions is around 1.0 second.
Slide 13 - Slide
Braking distance
Reaction distance
Slide 14 - Drag question
A horse runs to the finishline at 39.6 km/h. The drivers reaction time is 0.2 s. The braking distance is 22.8 m. Determine the stopping distance.
Formulas:
stopping distance = reaction distance + braking distance
reaction distance = reaction time x velocity
Slide 15 - Slide
A horse runs to the finishline at 39.6 km/h. The drivers reaction time is 0.2 s. The braking distance is 22.8 m. Determine the stopping distance.
Slide 16 - Open question
v = 39.6 km/h = 11 m/s (39.6 / 3.6)
t = 0.2 s (reaction time)
braking distance = 22.8m
stopping distance = reaction distance + braking distance
reaction distance
= v x t = 11 x 0.2 = 2.2 m
stopping distance = reaction distance + braking distance
stopping distance = 22.8 + 2.2 = 25m
Slide 17 - Slide
Homework
6.4 Exercises
HAVO: 36 / 37 / 38 / 40 / 42
Page 200
Slide 18 - Slide
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