This lesson contains 10 slides, with interactive quiz and text slides.
Lesson duration is: 50 min
Items in this lesson
Centripetal force
Bluetooth
- ON
- VPN off
Stationary
- Writing book
- Pen and pencil
- Calculator
- iPad
Mark
- NO
Lessonup
- YES
Schoolbags in
the cupboard
Phones in the phonebag
Slide 1 - Slide
Lesson goals:
Calculate the centripetal force with the formula:
Calculate mass, velocity and
radius with the same formula
Fcpf=rm⋅v2
Slide 2 - Slide
Centripetal force
For an object to move in a circular motion a centripetal force is needed.
This force is always directed to the centre of the circle.
The size of the force you can calculate with the formula:
Fcpf=rm⋅v2
= centripetal force (N)
m = mass (kg)
v = velocity (m/s)
r = radius (m)
Fcpf
Slide 3 - Slide
Example:
A satellite of 720 kg circulates the earth above the radius with a velocity of
27 000 km/h. The satellite is at a height of 680 km above the earth. The radius of the earth at the equator is 6370 km. Calculate the gravitational force with which the earth attracts the satellite.
Define problem:
Calcualtion:
therefore
Slide 4 - Slide
Try by yourself
Which force is the centripetal force in the following situations:
a) A chair goes round and round in a mery-go-round.
b) A car drives through a bend.
c) The moon 'Europe' circulates Jupiter.
timer
2:30
Slide 5 - Slide
a) The cable that attaches the chair to the mery-go-round.
b) The friction between the tyres of the car and the road surface.
c) The gravitational force between Jupiter and its moon 'Europe'.
Slide 6 - Slide
Try the following
A satellite (m = 2100 kg) circles the earth in 6 hours. The height of the satellite above the earths surface is 10 400 km. The radius of the earth is 6371 km.
a) Calculate the distance from the satellite to the centre of the earth.
b) Calculate the velocity of the satellite.
c) Calculate the centripetal force on the satellite.
timer
4:00
Slide 7 - Slide
The length of a complete rotation around the earth is