21/10: Chemical equations

• Chemistry
• Secondary Education

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CHEMISTRY 10

                   19: Chemical equations

Week 11

Good Morning!

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CHEMISTRY 10

                   19: Chemical equations

Week 11

write word equations and symbol equations to show how reactants form products with state symbols

deduce the symbol equation with state symbols for a chemical reaction, given relevant information

assess my thinking and how I learn to identify growth areas and improve my learning.

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CHEMISTRY 10

                   19: Chemical equations

Week 11

What is the Mᵣ of copper (II) oxide?

What is a reactant?

What is a product?

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CHEMISTRY 10

                   19: Chemical equations

Week 11

Try this!

Given the description of the chemical reaction, write a word equation.

Chemical reaction

Potassium reacts vigorously when it comes in contact with water, producing potassium hydroxide and hydrogen gas.

potassium + water → potassium hydroxide + hydrogen

Word equation

Reactant 1

Product 1

Product 2

Reactant 2

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Word equation

Symbol equation

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Word equation

Symbol equation

Symbol equation with state symbols

How can you make a word equation easier and shorter to write?

potassium + water → potassium hydroxide + hydrogen

K + H₂O → KOH + H₂

K(s) + H₂O (l) → KOH(aq) + H₂ (g)

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Word equation

Symbol equation

Symbol equation with state symbols

Balanced symbol equation with state symbols

Balanced chemical (symbol) equation

• a summary of a chemical reaction using chemical formulae
• the total number of atoms involved is the same on both the reactant and product sides of the equation

Balanced chemical (symbol) equation

• a summary of a chemical reaction using chemical formulae
• the total number of atoms involved is the same on both the reactant and product sides of the equation

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Balanced chemical (symbol) equation

• a summary of a chemical reaction using chemical formulae
• the total number of atoms involved is the same on both the reactant and product sides of the equation

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

Balanced chemical (symbol) equation

• a summary of a chemical reaction using chemical formulae
• the total number of atoms involved is the same on both the reactant and product sides of the equation

2K(s) + 2H₂O (l) → 2KOH(aq) + H₂ (g)

REACTANTS

PRODUCTS

K = 2 X 1 = 2

H = 2 X 2 = 4

O = 2 X 1 = 2

K = 2 X 1 = 2

H = 2 X 1 = 2   +    H = 2

O = 2 X 1 = 2

I can write word equations and symbol equations to show how reactants form products with state symbols

Yes, I can confidently do it.

Yes, I can but need more practice.

No, I lack confidence so I need more practice or ask help from my teacher.

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CHEMISTRY 10

                   19: Chemical equations

Week 11

Sample 1

• Iron rusts because it reacts with oxygen in the air to form a compound called iron (III) oxide.

a chemical reaction → a word equation → a symbol equation with state symbols → balanced symbol equation

Sample 2

• 2NaOH (solid) + H₂SO₄ (aqueous) → Na₂SO₄ (aqueous)+ 2H₂O (liquid)

a chemical reaction ⬅️ a word equation ⬅️ a symbol equation with state symbols ⬅️ balanced symbol equation

I can deduce the symbol equation with state symbols for a chemical reaction, given relevant information.

Yes, I can confidently do it.

Yes, I can but need more practice.

No, I lack confidence so I need more practice or ask help from my teacher.

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CHEMISTRY 10

                   19: Chemical equations

Week 11

Practice your skill:

Part 1. Choose one only.

(a) Sodium reacts vigorously with water to give a sodium hydroxide solution; hydrogen gas is also given off.

(b) A white precipitate is formed when silver nitrate is added to sodium chloride solution. This white precipitate is silver chloride, which is highly insoluble in water. This is why silver nitrate solution is used to detect the presence of halide ions.

a chemical reaction → a word equation → a symbol equation with state symbols → balanced symbol equation

Practice your skill:

Part 2. Choose one only.

 (a) 2K (solid) + 2HCl (liquid) → 2KCl (aqueous) + H₂ (gas)

 (b) 2Al (solid) + 3Cl₂ (gas) → 2AlCl₃ (solid) 

a chemical reaction ⬅️ a word equation ⬅️ a symbol equation with state symbols ⬅️ balanced symbol equation

Share your thought process in calculating the relative molecular/formula mass.

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CHEMISTRY 10

                   19: Chemical equations

Week 11

Classwork 9: Stoichiometry (part 2)

Apply your learned knowledge and skills:

Choose one (2 marks)

Write the word and balanced symbol equations.

Option 1: When added to dilute hydrochloric acid, copper carbonate fizzes and releases carbon dioxide gas. The resulting solution is copper chloride and water.

Option 2: Magnesium carbonate fizzes and releases carbon dioxide gas when added to dilute sulfuric acid. The resulting solution is magnesium sulfate and water.

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CHEMISTRY 10

                   19: Chemical equations

Week 11

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STEM Project

Building a Futuristic City Scale Model

Week 11

Share your thought process in calculating the relative molecular/formula mass.