C3H6 + H
2O -->
C3H7OH
1,0 kg = 1000 gram
Mpropeen = 42,08 g/mol
1000 g / M = 23,8 mol propeen molverhouding 1:1 -> 23,8 mol propaan-1-ol
Mpropaan-1-ol = 60,09 g/mol
dus de theoretische opbrengst is 23,8 x M = 1,4 kg propaan-1-ol
rendement = 0,80 / 1,4 x 100% = 56 %