Cette leçon contient 14 diapositives, avec quiz interactifs et diapositives de texte.
La durée de la leçon est: 45 min
Éléments de cette leçon
What have we discussed up to now?
Combustion reactions
Decomposition reactions
Electrolysis
Thermolysis
Slide 1 - Diapositive
What substance always takes part in a combustion reaction? (full name)
Slide 2 - Question ouverte
Which of these equations is characteristic for a decomposition reaction?
A
A + B → AB
B
AB → A + B
C
AB → C + D
D
A + B → C
Slide 3 - Quiz
Look at the image. How many grams of oxygen are used in this reaction? one decimal number.
8.0 g
Slide 4 - Question ouverte
Finding the limiting reactant
When there is not enough of one reactant in a chemical reaction, the reaction stops abruptly. To figure out the amount of product produced, it must be determined which reactant will limit the chemical reaction (the limiting reagent) and which reactant is in excess (the excess reagent).
Slide 5 - Diapositive
For example:
Substance A and substance B respectively react in a mass ratio of 5g:10g.
10 grams of both substance A and substance B are mixed in a jar and they react with eachother.
How many grams of which substance will remain after the reaction?
5 grams of substance B
Slide 6 - Diapositive
Steps to find the limiting/excess reactant
Balance equation
Find mass ratio with periodic table
Mark with X
Use Cross product
If needed, calculate mass of the product
Slide 7 - Diapositive
Slide 8 - Diapositive
Slide 9 - Diapositive
Slide 10 - Diapositive
Slide 11 - Diapositive
Slide 12 - Diapositive
Now, it's your turn.
Calculate the mass of magnesium oxide (MgO)that is created when 2.4 g Mg reacts with 10.0 g O2
Remember the steps:
Find the limiting reagent by looking at the number of grams of each reactant.
Determine the balanced chemical equation for the chemical reaction.
Use your periodic table and balanced reaction equation to find the mass ratio.
Find the limiting/excess reactant by marking it with an X.
Use cross products to calculate the mass of the other reactant.