Lesson 12

First name: George
Guess his last name.

1 / 14

Slide 1: Diapositive

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Cette leçon contient 14 diapositives, avec diapositives de texte.

La durée de la leçon est: 45 min

Éléments de cette leçon

First name: George
Guess his last name.

Slide 1 - Diapositive

George Ohm

Shared Ohm's law with the public in 1827.

Ohm's law is used in designing the electrical circuits in all our technology.

Slide 2 - Diapositive

Current, voltage and resistance.

Current: the flow of charged particles from one point in a circuit to another. Expressed in amperes (Coulomb / second)

Voltage: The difference in electrical potential energy between two points in a circuit. Expressed in volts (Joules / second)

Resistance: The opposition to the flow of charged particles. Expressed in Ohms.

Slide 3 - Diapositive

Which of these three is incorrect?

C u r r e n t = \frac{​ R e s i s t a n c e ​ ​}{​ v o l t a g e ​}

C u r r e n t = \frac{​ V o l t a g e ​ ​}{​ R e s i s t a n c e ​}

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ C u r r e n t ​}

Slide 4 - Diapositive

This lesson

Intro
Rearranging Ohms law
Discussing the homework
Time to study

Slide 5 - Diapositive

Learning goals

You can name who discovered Ohm's law (not required for the test)

You can describe the relationship between current, voltage and resistance – Ohm's law.
You are able to Rearrange Ohm's law
You are able to apply Ohm's law in calculations.

Slide 6 - Diapositive

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 7 - Diapositive

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 8 - Diapositive

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 9 - Diapositive

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n t \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 10 - Diapositive

R = \frac{​ V ​ ​}{​ I ​}

V = I \cdot R

I = \frac{​ V ​ ​}{​ R ​}

C u r r e n t = \frac{​ v o l t a g e ​ ​}{​ r e s i s t a n c e ​}

V o l t a g e = c u r r e n \cdot r e s i s t a n c e

R e s i s t a n c e = \frac{​ V o l t a g e ​ ​}{​ c u r r e n t ​}

Rearrange the formula

In words

In symbols

Slide 11 - Diapositive

Discussing the homework

Slide 12 - Diapositive

3 lamps are connected to a battery in a parallel circuit. The battery supplies the circuit with 2.4 Ampere.

Because of its resistance, the second lamp gets 2/3 of the current supplied to the circuit. The rest of the current gets divided evenly over the other two lamps.

The voltage over the battery is 6 Volts.

Calculate the resistance of each lamp.

Slide 13 - Diapositive

Learning goals

You can name who discovered Ohm's law (not required for the test)

You can describe the relationship between current, voltage and resistance – Ohm's law.
You are able to Rearrange Ohm's law
You are able to apply Ohm's law in calculations.

Slide 14 - Diapositive

Lesson 12

Éléments de cette leçon

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Slide 2 - Diapositive

Slide 3 - Diapositive

Slide 4 - Diapositive

Slide 5 - Diapositive

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Slide 14 - Diapositive

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