6.4 Braking and collisions

6.4 Braking and collisions
2THa
1 / 18
volgende
Slide 1: Tekstslide
NatuurkundeMiddelbare schoolhavo, vwoLeerjaar 2

In deze les zitten 18 slides, met interactieve quizzen en tekstslides.

time-iconLesduur is: 30 min

Onderdelen in deze les

6.4 Braking and collisions
2THa

Slide 1 - Tekstslide

6.4 Braking and collisions

Slide 2 - Tekstslide

In traffic you always have to able to stop in time without having a collision.

Slide 3 - Tekstslide

What factors will influence the braking distance?
A
Mass of the car
B
Braking force
C
Speed of the car
D
All answers above

Slide 4 - Quizvraag

The higher the initial speed,
the longer the braking distance.

Slide 5 - Tekstslide

The greater the mass of the vehicle,
the longer the breaking distance.

Slide 6 - Tekstslide

If the road is slippery you have to brake slowly, othewise the car will slip.

Slide 7 - Tekstslide

And sometimes the brakes just fail....

Slide 8 - Tekstslide

Braking distance

Depends on:

  • Initial speed;
    the faster you are going, the greater the braking distance
  • Total mass;
    the greater the mass the greater the braking distance
  • Braking force;
    the harder the brakes are pressed the shorter the braking distance

Slide 9 - Tekstslide

Slide 10 - Tekstslide

Stopping distance = reaction distance + braking distance

Slide 11 - Tekstslide

Reaction time
Make pairs
Fold you paper 3x double

Nr.1 has his hand open
Nr.2 determince when to let go
Nr.1 has to react

Slide 12 - Tekstslide

Reaction distance

Reaction distance  =  reaction time  x  velocity

The reaction time in normal conditions is around 1.0 second.

Slide 13 - Tekstslide

Braking distance
Reaction distance

Slide 14 - Sleepvraag

A horse runs to the finishline at 39.6 km/h. The drivers reaction time is 0.2 s. The braking distance is 22.8 m. Determine the stopping distance.

Formulas:
stopping distance = reaction distance + braking distance
reaction distance = reaction time x velocity

Slide 15 - Tekstslide

A horse runs to the finishline at 39.6 km/h. The drivers reaction time is 0.2 s. The braking distance is 22.8 m. Determine the stopping distance.

Slide 16 - Open vraag

  v = 39.6 km/h = 11 m/s (39.6 / 3.6)
  t = 0.2 s (reaction time)
  braking distance = 22.8m 

stopping distance = reaction distance + braking distance

reaction distance = v x t = 11 x 0.2 = 2.2 m
           stopping distance = reaction distance + braking distance
           stopping distance = 22.8 + 2.2 = 25m

Slide 17 - Tekstslide

Homework
6.4 Exercises
HAVO: 36 / 37 / 38 / 40 / 42
Page 200

Slide 18 - Tekstslide