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Solving 1-Step Equations
Solving Equations
Solving 1- Step
Equations
11/4/24
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Slide 1:
Tekstslide
Math
7th Grade
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12 slides
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interactieve quizzen
en
tekstslides
.
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Solving Equations
Solving 1- Step
Equations
11/4/24
Slide 1 - Tekstslide
Objectives:
-Understand the process to solving 1-Step equations.
- Identify the operation neccessary to solve 1-step equations.
-Solve 1-step equations.
Slide 2 - Tekstslide
Addition and Subtraction
If you are moving a
positive
number to the other side of the equal sign, then you will use
subtraction
.
If you are moving a
negative
number to the other side of the equal sign, then you will use
addition
.
x
+
2
=
0
3
+
x
=
1
2
=
x
+
5
4
=
1
+
x
Examples:
Examples:
x
−
5
=
0
−
2
+
x
=
3
−
1
=
−
4
+
x
2
=
x
−
6
First
, you have to identify which operation you will need to use to get by itself.
x
Slide 3 - Tekstslide
Addition and Subtraction
Second,
use the identified operation to add or subtract the value to both sides of the equation.
Examples:
x
+
2
=
0
−
2
−
2
x
−
5
=
0
+
5
+
5
2
=
x
+
5
4
=
1
+
x
3
+
x
=
1
−
2
+
x
=
3
2
=
x
−
6
−
1
=
−
4
+
x
−
5
−
5
−
1
−
1
−
3
−
3
+
6
+
6
+
2
+
2
+
4
+
4
Slide 4 - Tekstslide
Addition and Subtraction
Third,
carry out the appropriate operation to solve for .
Examples:
x
+
2
=
0
−
2
−
2
x
−
5
=
0
+
5
+
5
2
=
x
+
5
4
=
1
+
x
3
+
x
=
1
−
2
+
x
=
3
2
=
x
−
6
−
1
=
−
4
+
x
−
5
−
5
−
1
−
1
−
3
−
3
+
6
+
6
+
2
+
2
+
4
+
4
x
x
=
−
2
x
=
3
x
=
−
3
x
=
−
2
x
=
5
x
=
5
x
=
8
x
=
3
Slide 5 - Tekstslide
Identify the operation needed to solve for .
x
Addition
Subtraction
x + 2 = 5
x - 3 = 4
-3 + x = 6
4 + x = 3
2 = x - 3
0 = -5 + x
1 = 4 + x
6 = x + 4
Slide 6 - Sleepvraag
Division and Multiplication
If is being
multiplied
by a number, then you will use
division
.
If is being
divided
by a number, then you will use
multiplication
.
Examples:
Examples:
First
, you have to identify which operation you will need to use to get by itself.
x
x
x
3
x
=
0
−
2
x
=
4
1
=
2
x
3
=
−
6
x
2
x
=
0
−
3
x
=
2
1
=
4
x
2
=
−
5
x
Slide 7 - Tekstslide
Division and Multiplication
Examples:
Second
, use the identified operation to divide or multiply both sides of the equation by the value.
3
3
x
=
3
0
−
2
−
2
x
=
−
2
4
2
1
=
2
2
x
−
6
3
=
−
6
−
6
x
2
x
⋅
2
=
0
⋅
2
−
3
x
⋅
−
3
=
2
⋅
−
3
1
⋅
4
=
4
x
⋅
4
2
⋅
−
5
=
−
5
x
⋅
−
5
Slide 8 - Tekstslide
Division and Multiplication
Examples:
Third
, carry out the appropriate operation to solve for .
3
3
x
=
3
0
−
2
−
2
x
=
−
2
4
2
1
=
2
2
x
−
6
3
=
−
6
−
6
x
2
x
⋅
2
=
0
⋅
2
−
3
x
⋅
−
3
=
2
⋅
−
3
1
⋅
4
=
4
x
⋅
4
2
⋅
−
5
=
−
5
x
⋅
−
5
x
x
=
0
x
=
−
2
x
=
2
1
x
=
−
2
1
x
=
0
x
=
4
x
=
−
6
x
=
−
1
0
Slide 9 - Tekstslide
Identify the operation needed to solve for .
x
Division
Multiplication
x/3 = 4
4x = 4
x/2 = -6
-3x = 5
2 = 6x
0 = x/-5
1 = -4x
6 = x/4
Slide 10 - Sleepvraag
Questions?
Complaints?
Concerns?
Comments?
Slide 11 - Tekstslide
Assess Your Understanding:
-
Go to
play.blooket.com
.
-Enter the code XXXXXXX.
-Your nickname will be your first initial followed by your last name.
-Wait patiently for me to start the game.
(
Name:
Karissa Goula
Nickname:
KGoula)
Slide 12 - Tekstslide
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