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herleiden van breuken
Voor we starten
Boek, schrift en etui op tafel
1 / 38
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Slide 1:
Slide
Wiskunde
Middelbare school
vwo
Leerjaar 1
This lesson contains
38 slides
, with
text slides
.
Lesson duration is:
30 min
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Items in this lesson
Voor we starten
Boek, schrift en etui op tafel
Slide 1 - Slide
Voor we starten
Vragen?
Slide 2 - Slide
Wat gaan we doen?
Vandaag: Herleiden van breuken met variabelen
Slide 3 - Slide
Mijn favoriete misser
Bereken b voor k = 3
b
=
k
2
−
2
Slide 4 - Slide
Herleiden van breuken
§6.6
Slide 5 - Slide
Wat doe je allemaal met breuken?
Slide 6 - Slide
Wat doe je allemaal met breuken?
vereenvoudigen
optellen en aftrekken
vermenigvuldigen
delen
Slide 7 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
Slide 8 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
1
2
8
Slide 9 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
1
2
8
=
3
⋅
4
2
⋅
4
Slide 10 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
1
2
8
=
3
⋅
4
2
⋅
4
/
/
=
3
2
Slide 11 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
1
2
8
=
3
⋅
4
2
⋅
4
/
/
=
3
2
x
5
x
Slide 12 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
1
2
8
=
3
⋅
4
2
⋅
4
/
/
=
3
2
x
5
x
=
1
⋅
x
5
⋅
x
Slide 13 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
1
2
8
=
3
⋅
4
2
⋅
4
/
/
=
3
2
x
5
x
=
1
⋅
x
5
⋅
x
/
/
Slide 14 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
1
2
8
=
3
⋅
4
2
⋅
4
/
/
=
3
2
x
5
x
=
1
⋅
x
5
⋅
x
/
/
=
5
Slide 15 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
−
1
0
x
z
−
8
x
y
z
Slide 16 - Slide
Gelijknamige breuken
optellen en aftrekken
§6.6 Theorie B
Slide 17 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
7
3
+
7
2
=
7
5
Slide 18 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
7
3
+
7
2
=
7
5
y
3
+
y
2
=
Slide 19 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
7
3
+
7
2
=
7
5
y
3
+
y
2
=
y
5
Slide 20 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
a
b
8
−
a
b
3
=
Slide 21 - Slide
Niet-gelijknamige breuken
optellen en aftrekken
§6.6 Theorie C
Slide 22 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
3
2
+
7
1
=
Slide 23 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
3
2
+
7
1
=
3
⋅
7
2
⋅
7
+
7
⋅
3
1
⋅
3
=
Slide 24 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
3
2
+
7
1
=
3
⋅
7
2
⋅
7
+
7
⋅
3
1
⋅
3
=
2
1
1
4
+
2
1
3
=
Slide 25 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
3
2
+
7
1
=
3
⋅
7
2
⋅
7
+
7
⋅
3
1
⋅
3
=
2
1
1
4
+
2
1
3
=
2
1
1
7
Slide 26 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
3
2
+
7
1
=
3
⋅
7
2
⋅
7
+
7
⋅
3
1
⋅
3
=
2
1
1
4
+
2
1
3
=
2
1
1
7
x
2
+
y
1
=
Slide 27 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
3
2
+
7
1
=
3
⋅
7
2
⋅
7
+
7
⋅
3
1
⋅
3
=
2
1
1
4
+
2
1
3
=
2
1
1
7
x
2
+
y
1
=
x
⋅
y
2
⋅
y
+
y
⋅
x
1
⋅
x
=
Slide 28 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
3
2
+
7
1
=
3
⋅
7
2
⋅
7
+
7
⋅
3
1
⋅
3
=
2
1
1
4
+
2
1
3
=
2
1
1
7
x
2
+
y
1
=
x
⋅
y
2
⋅
y
+
y
⋅
x
1
⋅
x
=
x
y
2
y
+
x
y
3
x
=
Slide 29 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
3
2
+
7
1
=
3
⋅
7
2
⋅
7
+
7
⋅
3
1
⋅
3
=
2
1
1
4
+
2
1
3
=
2
1
1
7
x
2
+
y
1
=
x
⋅
y
2
⋅
y
+
y
⋅
x
1
⋅
x
=
x
y
2
y
+
x
y
3
x
=
x
y
3
x
+
2
y
Slide 30 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
6
5
−
1
2
1
=
Slide 31 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
6
5
−
1
2
1
=
6
⋅
2
5
⋅
2
−
1
2
1
=
Slide 32 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
6
5
−
1
2
1
=
6
⋅
2
5
⋅
2
−
1
2
1
=
1
2
1
0
−
1
2
1
=
Slide 33 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
6
5
−
1
2
1
=
6
⋅
2
5
⋅
2
−
1
2
1
=
1
2
1
0
−
1
2
1
=
1
2
9
Slide 34 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
6
5
−
1
2
1
=
6
⋅
2
5
⋅
2
−
1
2
1
=
1
2
1
0
−
1
2
1
=
1
2
9
x
2
−
2
x
y
3
=
Slide 35 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
6
5
−
1
2
1
=
6
⋅
2
5
⋅
2
−
1
2
1
=
1
2
1
0
−
1
2
1
=
1
2
9
x
2
−
2
x
y
3
=
x
⋅
2
⋅
y
2
⋅
2
⋅
y
−
2
x
y
3
=
Slide 36 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
6
5
−
1
2
1
=
6
⋅
2
5
⋅
2
−
1
2
1
=
1
2
1
0
−
1
2
1
=
1
2
9
x
2
−
2
x
y
3
=
x
⋅
2
⋅
y
2
⋅
2
⋅
y
−
2
x
y
3
=
2
x
y
4
y
−
2
x
y
3
=
Slide 37 - Slide
Breuken vereenvoudigen
§6.6 Theorie A
6
5
−
1
2
1
=
6
⋅
2
5
⋅
2
−
1
2
1
=
1
2
1
0
−
1
2
1
=
1
2
9
x
2
−
2
x
y
3
=
x
⋅
2
⋅
y
2
⋅
2
⋅
y
−
2
x
y
3
=
2
x
y
4
y
−
2
x
y
3
=
2
x
y
4
y
−
3
Slide 38 - Slide
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