Uitwerking meerkeuzevraag
βπ=πβπ=πβπβπ
π_ππππ=ππ
π/π=1000/18β8,314β293/10^5 =1,353π^3
π_π€ππ‘ππ=0,001 π^3
πβπ=π(π_ππππβπ_π€ππ‘ππ )=1,35β10^5 π½
βπ=2,256β10^6β0,135β10^6=2,12β10^6 π½