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workshop H9
Workshop over H9
SO vrijdag 19 maart
6e uur
Online voor H3B en H3C,
Op school H3A (op laptop of papier)
1 / 43
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Slide 1:
Slide
Wiskunde
Middelbare school
havo
Leerjaar 3
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Items in this lesson
Workshop over H9
SO vrijdag 19 maart
6e uur
Online voor H3B en H3C,
Op school H3A (op laptop of papier)
Slide 1 - Slide
H9 gaat over 3 onderwerpen
1. (Letter)rekenen met breuken
2. (letter)rekenen met machten
3. (Letter)rekenen met wortels
Slide 2 - Slide
Rekenregels (krijg je erbij)
Breuken machten wortels
:
b
a
+
b
c
=
b
a
+
c
b
a
+
d
c
=
b
d
a
d
+
c
b
b
a
⋅
d
c
=
b
d
a
c
b
a
g
a
⋅
g
b
=
g
a
+
b
(
g
a
)
b
=
g
a
⋅
b
d
c
=
b
a
⋅
c
d
=
b
c
a
d
g
b
g
a
=
g
a
−
b
√
a
⋅
√
b
=
√
a
⋅
b
√
a
+
√
b
=
√
a
+
√
b
√
b
√
a
=
√
b
a
(
b
a
)
n
=
b
n
a
n
(
a
⋅
b
)
n
=
a
n
⋅
b
n
Slide 3 - Slide
rekenen met breuken
5
0
2
5
x
+
2
0
Slide 4 - Slide
rekenen met breuken
5
0
2
5
x
+
2
0
=
5
0
2
5
x
+
5
0
2
0
=
Slide 5 - Slide
rekenen met breuken
5
0
2
5
x
+
2
0
=
5
0
2
5
x
+
5
0
2
0
=
2
1
x
+
5
2
=
2
x
+
5
2
Slide 6 - Slide
rekenen met machten
(
3
2
+
2
x
−
5
+
4
x
2
y
)
3
Slide 7 - Slide
Rekenregels (krijg je erbij)
Breuken machten wortels
:
b
a
+
b
c
=
b
a
+
c
b
a
+
d
c
=
b
d
a
d
+
c
b
b
a
⋅
d
c
=
b
d
a
c
b
a
g
a
⋅
g
b
=
g
a
+
b
(
g
a
)
b
=
g
a
⋅
b
d
c
=
b
a
⋅
c
d
=
b
c
a
d
g
b
g
a
=
g
a
−
b
√
a
⋅
√
b
=
√
a
⋅
b
√
a
+
√
b
=
√
a
+
√
b
√
b
√
a
=
√
b
a
(
b
a
)
n
=
b
n
a
n
(
a
⋅
b
)
n
=
a
n
⋅
b
n
Slide 8 - Slide
rekenen met machten
(
3
2
+
2
x
−
5
+
4
x
2
y
)
3
Slide 9 - Slide
rekenen met machten
(
3
2
+
2
x
−
5
+
4
x
2
y
)
3
(
3
2
)
3
+
(
2
x
)
3
+
(
−
5
)
3
+
4
3
x
6
y
3
Slide 10 - Slide
rekenen met machten
(
3
2
+
2
x
−
5
+
4
x
2
y
)
3
(
3
2
)
3
+
(
2
x
)
3
+
(
−
5
)
3
+
4
3
x
6
y
3
3
3
2
3
+
8
x
3
+
−
1
2
5
+
6
4
x
6
y
3
Slide 11 - Slide
rekenen met machten
(
3
2
+
2
x
−
5
+
4
x
2
y
)
3
(
3
2
)
3
+
(
2
x
)
3
+
(
−
5
)
3
+
4
3
x
6
y
3
2
7
8
+
8
x
3
+
−
1
2
5
+
6
4
x
6
y
3
Slide 12 - Slide
Rekenen met machten en breuken
5
x
y
1
5
x
3
y
Slide 13 - Slide
Rekenregels (krijg je erbij)
Breuken machten wortels
:
b
a
+
b
c
=
b
a
+
c
b
a
+
d
c
=
b
d
a
d
+
c
b
b
a
⋅
d
c
=
b
d
a
c
b
a
g
a
⋅
g
b
=
g
a
+
b
(
g
a
)
b
=
g
a
⋅
b
d
c
=
b
a
⋅
c
d
=
b
c
a
d
g
b
g
a
=
g
a
−
b
√
a
⋅
√
b
=
√
a
⋅
b
√
a
+
√
b
=
√
a
+
√
b
√
b
√
a
=
√
b
a
(
b
a
)
n
=
b
n
a
n
(
a
⋅
b
)
n
=
a
n
⋅
b
n
Slide 14 - Slide
Rekenen met machten en breuken
5
x
y
1
5
x
3
y
Slide 15 - Slide
Rekenen met machten en breuken
5
x
y
1
5
x
3
y
=
3
x
2
Slide 16 - Slide
Rekenen met wortels
√
7
5
x
2
Slide 17 - Slide
Rekenregels (krijg je erbij)
Breuken machten wortels
:
b
a
+
b
c
=
b
a
+
c
b
a
+
d
c
=
b
d
a
d
+
c
b
b
a
⋅
d
c
=
b
d
a
c
b
a
g
a
⋅
g
b
=
g
a
+
b
(
g
a
)
b
=
g
a
⋅
b
d
c
=
b
a
⋅
c
d
=
b
c
a
d
g
b
g
a
=
g
a
−
b
√
a
⋅
√
b
=
√
a
⋅
b
√
a
+
√
b
=
√
a
+
√
b
√
b
√
a
=
√
b
a
(
b
a
)
n
=
b
n
a
n
(
a
⋅
b
)
n
=
a
n
⋅
b
n
Slide 18 - Slide
Rekenen met wortels
√
7
5
x
2
Slide 19 - Slide
Rekenen met wortels
√
7
5
x
2
=
√
3
⋅
2
5
⋅
x
2
Slide 20 - Slide
Rekenen met wortels
√
7
5
x
2
=
√
3
⋅
2
5
⋅
x
2
=
√
3
⋅
√
2
5
⋅
√
x
2
Slide 21 - Slide
Rekenen met wortels
√
7
5
x
2
=
√
3
⋅
2
5
⋅
x
2
=
√
3
⋅
√
2
5
⋅
√
x
2
=
√
3
⋅
5
⋅
x
Slide 22 - Slide
Rekenen met wortels
=
5
x
√
3
√
7
5
x
2
=
√
3
⋅
2
5
⋅
x
2
=
√
3
⋅
√
2
5
⋅
√
x
2
=
√
3
⋅
5
⋅
x
Slide 23 - Slide
Rekenen met wortels
√
1
9
7
Slide 24 - Slide
Rekenregels (krijg je erbij)
Breuken machten wortels
:
b
a
+
b
c
=
b
a
+
c
b
a
+
d
c
=
b
d
a
d
+
c
b
b
a
⋅
d
c
=
b
d
a
c
b
a
g
a
⋅
g
b
=
g
a
+
b
(
g
a
)
b
=
g
a
⋅
b
d
c
=
b
a
⋅
c
d
=
b
c
a
d
g
b
g
a
=
g
a
−
b
√
a
⋅
√
b
=
√
a
⋅
b
√
a
+
√
b
=
√
a
+
√
b
√
b
√
a
=
√
b
a
(
b
a
)
n
=
b
n
a
n
(
a
⋅
b
)
n
=
a
n
⋅
b
n
Slide 25 - Slide
Rekenen met wortels
√
1
9
7
Slide 26 - Slide
Rekenen met wortels
√
1
9
7
=
√
9
1
6
Slide 27 - Slide
Rekenen met wortels
√
1
9
7
=
√
9
1
6
=
√
9
√
1
6
Slide 28 - Slide
Rekenen met wortels
√
1
9
7
=
√
9
1
6
=
√
9
√
1
6
=
3
4
Slide 29 - Slide
Rekenen met wortels
√
1
9
7
=
√
9
1
6
=
√
9
√
1
6
=
3
4
=
1
3
1
Slide 30 - Slide
De regels worden steeds gecombineerd
1
6
3
4
5
x
⋅
(
4
2
)
3
⋅
4
x
=
Slide 31 - Slide
De regels worden steeds gecombineerd
1
6
3
4
5
x
⋅
(
4
2
)
3
⋅
4
x
=
(
4
2
)
3
4
6
x
+
6
Slide 32 - Slide
De regels worden steeds gecombineerd
1
6
3
4
5
x
⋅
(
4
2
)
3
⋅
4
x
=
4
6
4
6
x
+
6
=
Slide 33 - Slide
De regels worden steeds gecombineerd
1
6
3
4
5
x
⋅
(
4
2
)
3
⋅
4
x
=
4
6
4
6
x
+
6
=
4
6
x
Slide 34 - Slide
1
6
3
4
5
x
⋅
(
4
2
)
3
⋅
4
x
=
1
6
3
4
5
x
⋅
(
4
2
)
3
⋅
4
x
=
Slide 35 - Open question
gecombineerde regels
√
6
k
√
5
4
k
2
=
Slide 36 - Slide
Slide 37 - Open question
gecombineerde regels
√
6
k
√
5
4
k
2
=
Slide 38 - Slide
gecombineerde regels
√
6
k
√
5
4
k
2
=
√
6
k
5
4
k
2
Slide 39 - Slide
gecombineerde regels
√
6
k
√
5
4
k
2
=
√
6
k
5
4
k
2
=
√
6
⋅
k
9
⋅
6
⋅
k
⋅
k
Slide 40 - Slide
gecombineerde regels
√
6
k
√
5
4
k
2
=
√
6
k
5
4
k
2
=
√
6
⋅
k
9
⋅
6
⋅
k
⋅
k
=
√
9
k
Slide 41 - Slide
gecombineerde regels
√
6
k
√
5
4
k
2
=
√
6
k
5
4
k
2
=
√
6
⋅
k
9
⋅
6
⋅
k
⋅
k
=
√
9
k
=
3
√
k
Slide 42 - Slide
zijn er nog vragen?
Slide 43 - Open question
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