14,89 mL x 0,1008 M (mmol/mL) = 1,500912 mmol H
3O
+
Ammoniak reageert 1 : 1 met zoutzuur, dus ook 1,500912 mmol NH3.
1,500912 mmol NH3 zat in 10 mL oplossing. Dus 0,1500912 M oplossing.
We hebben 20x verdund, dus de originele oplossing was 20 x 0,1500912 = 3,001824 M.
3,001824 mol NH3 in 1 liter, dus 3,001824 * 17,034 = 51,133 gram per liter.
1 liter water = 998,2 g. Totaal dus 998,2 + 51,133 = 1049,333 gram.
Mass% = 51,133 / 1049,333 * 100% = 4,873 %massa